How to test the 12V of electric bolt lock?
Testing the 12V electric bolt lock mainly involves checking whether the 12V output is normal, and testing the pull-in and release of the relay.
First, at the beginning of the test, the 12V output should be energized, which is the normal state. Next, the relay should be pulled in by short-circuiting PUSH and ground, causing the 12V output to be disconnected, which is to retract the electromagnetic lock tongue. After that, the relay should be released, allowing the 12V output to be powered on again. If the relay is not released all the time, then the door cannot be locked, which is a problem that needs special attention in the test.
When adjusting the adjustable resistance of the locking time, it is found that when it is adjusted to the minimum, the relay is released, but this does not mean that the test is successful, because the time interval from power on to power off is too short (basically 0-1 second interval), which means that after pressing the door opening key, the door is locked almost instantly, which may not be ideal in actual application. Therefore, if there is a problem when the relay adjusts the resistance, such as the 105 resistor mentioned in the test has an infinite resistance or a resistance of 0 ohms when adjusted to the minimum, this may indicate that the resistor is damaged and needs to be replaced.
Through such a test process, it can be ensured that the electric bolt lock can work normally under a 12V power supply, and the relay's attraction and release can also meet the use requirements, thereby ensuring the door's locking and unlocking functions are normal.
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